Question

10. A road roller takes 750 revolutions to move once to

level a playground. Find the area of the ground if the
diameter of the road roller is 168 cm and length is 2.8
m.​

Answer 1

Explanation:

Use consistent units. The length of the roller is 2.8 m. The diameter is 168 cm = 1.68 m

Circumference of roller = 1.68π m

Contact area of roller = 1.68π × 2.8 = 4.704π m²

Each rotation levels 4.704π m² of the playground.

Area of playground = 750 rotations × (4.704π m²)/rotation

= 3528π m²

≈ 11,084 m²