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12 votes
12 votes
An acute angle, θ, is in a right triangle such that cos θ = 12/13. What is the Value of csc θ? (100 Points!)

13/12
13/5
5/13
5/12

User Kyle Owens
by
2.6k points

2 Answers

26 votes
26 votes

Answer:


\textsf{a)} \quad \text{cosec}\:\theta=(13)/(12)

Explanation:

Given cosine trigonometric identity:


\boxed{\cos\theta=(12)/(13)}

To find the value of cosec θ, use the trigonometric identity:


\boxed{\text{cosec}\; \theta=(1)/(\cos\theta)}

Substitute the given value of cos θ into the cosec θ identity:


\implies \text{cosec}\:\theta=(1)/((12)/(13))


\implies \text{cosec}\:\theta=1 / (12)/(13)


\implies \text{cosec}\:\theta=1 * (13)/(12)


\implies \text{cosec}\:\theta=(13)/(12)

Therefore, the value of cosec θ is:


\boxed{\text{cosec}\:\theta=(13)/(12)}

User SemanticUI
by
2.9k points
15 votes
15 votes

Answer:

csc θ = 13/12

Explanation:

cos θ = 12/13

Formula: cos θ = 1/cscθ

Its just the reciprocal.

solve:

1/csc θ = 12/13

csc θ = 13/12

User DeusAduro
by
3.0k points