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Solve for the missing arcs

Solve for the missing arcs-example-1
User AndreyP
by
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1 Answer

2 votes

Answer:

Explanation:

arc KL = 60°

arc LNK = 360° - 60°

arc NJK = 180°

angle JQN = 60°

arc JN = 60°

arc JM = 60°+55° = 115°

arc MN = 55°

arc MKN = 360° - 55° = 305°

arc JML = 180°

angle MQL = 180° - 55° - 60° = 65°

arc ML = 65°

arc LN = 55° + 65° = 120°

User Sanish
by
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