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3 votes
Find the moles of CaCO3 in 23.4 g of calcium carbonate

2 Answers

3 votes

Answer:

0.0326 moles

explanation

User Avishayp
by
7.1k points
4 votes

Answer:

0.234 mol

Step-by-step explanation:

m(CaCO3) = 23.4g

n(CaCO3) = ?

M(CaCO3) = 100.09 g/mol

n = m/M

n(CaCO3) = 23.4 / 100.09

= 0.234 mol (3 s.f.)

User Samel
by
7.0k points