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30 votes
30 votes
Gas

LA of certain mass occupies a volume of 650 cm3 under
a pressure of 760mmHg. Calculate the pressure under which
the volume of the
gas
cent
of its original volume
will be reduced by 10 per​

User Hacknightly
by
2.6k points

1 Answer

21 votes
21 votes

Answer:

844.4cm³

Step-by-step explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (cm³)

V2 = final volume (cm³)

According to the information in this question,

V1 = 650cm³

P1 = 760mmHg

P2 = ?

V2 = 10% reduction of V1

10% of 650 = 10/100 × 650

65

V2 = 650 - 65 = 585cm³

Using P1V1 = P2V2

P2 = P1V1 ÷ V2

P2 = (760 × 650) ÷ 585

P2 = 494000 ÷ 585

P2 = 844.44

final pressure (P2) = 844.4cm³

User Bidstrup
by
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