Question

The velocity V of an object dropped from a tall building is given by V = V64d, where dis

the distance, in feet, the object has dropped. Find the distance when the velocity is
32 ft/sec.

Answer 1

d = 0.0625 m

Explanation:

The velocity of an object dropped from a tall building is given by :

`v=√(64d)`

Where

d is the distance in feet

We need to find the distance when the velocity is 32 ft/s

Rearranging for d,

`v^2=64d\\\\d=(64)/(v^2)`

Put v = 32 ft/s

`d=(64)/(32^2)\\\\d=0.0625\ m`

So, the required distance is 0.0625 m.