Question

How many moles of Ba(OH)2 are present in 205 mL of 0.400 M Ba(OH)2​

Answer 1

0.082 moles

Step-by-step explanation:

To answer this question we'll need to use the definition of molarity:

• Molarity = moles / liters

We are given the molarity and mililiters, so now we convert 205 mL into L:

• 205 mL / 1000 = 0.205 L

Now we can calculate the number of moles:

0.400 M = moles / 0.205 L

• moles = 0.082 moles