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What is the radius of the circle whose equation is x2+y2=18​

1 Answer

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Answer:

r =
3√(2)

Explanation:

equation of a circle:
(x-a)^2+(y-b)^2=r^2

where (a, b) is the center and r is the radius

Therefore, for the equation
x^2+y^2=18

  • a = 0
  • b = 0
  • r² = 18

⇒ r =
√(18) =
3√(2)

User Bitswazsky
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