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I need help 7 to 10 lesson 17-2 Practice Find the area of each figure Use π = 3.14​

I need help 7 to 10 lesson 17-2 Practice Find the area of each figure Use π = 3.14​-example-1
User EL Kamel
by
2.5k points

2 Answers

16 votes
16 votes

Answer:

number 7 is 28.56 in

Explanation:

User Dunbar
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3.4k points
10 votes
10 votes

Answer:

7. 22.28 in.²

8. 76.26 in.²

9. 13.76 cm²

10. 49.74 cm²

Explanation:

7.

A square with side 4 in. and a semicircle with diameter 4 in., radius = 2 in.

area = area of square + area of semicircle

area = s² + πr²/2

area = (4 in.)² + 3.14(2 in.)²/2

area = 16 in.² + 6.28 in.²

area = 22.28 in.²

8.

A rectangle with length and width of 8 in. and 6 in. and 2 semicircles with diameter 6 in., radius = 3 in. The 2 semicircles combine to make one circle or radius 3 in.

area = area of rectangle + area of circle

area = LW + πr²

area = 8 in. × 6 in. + 3.14(3 in.)²

area = 48 in.² + 28.26 in.²

area = 76.26 in.²

9.

A circle inside a square. The area we need is the shaded area, so we need to subtract the area of the circle from the area of the square.

area = area of square - area of circle

area = s² - πr²

area = (8 cm)² - 3.14(4 cm)²

area = 64 cm² - 50.24 cm²

area = 13.76 cm²

10.

A circle inside a parallelogram. The area we need is the shaded area, so we need to subtract the area of the circle from the area of the parallelogram.

area = area of parallelogram - area of circle

area = bh - πr²

area = (13 cm)(6 cm) - 3.14(3 cm)²

area = 78 cm² - 28.26 cm²

area = 49.74 cm²

User Robert Lachner
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