Question

if the area of the field is 16b^2+60b-100 and one dimension is b+5, what would be the other dimension?

Answer 1

`l=16(b-1.25)`

Explanation:

Given that,

The area of the field is
`16b^2+60b-100`

One dimensions = (b+5)

The field is in the shape of a rectangle whose are is given by :

A = lb

Wher

l is the length or the other dimension

`l=(A)/(b)\\\\l=(16b^2+60b-100)/(b+5)\\\\l=((16(b+5)(b-1.25))/(b+5)\\\\l=16(b-1.25)`

So, the other dimension be
`16(b-1.25)`.