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If ΔABC ≅ ΔDEF by SSS and AB = 5x + 6 and DE = 3x +10, then what must be the value of x?
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If ΔABC ≅ ΔDEF by SSS and AB = 5x + 6 and DE = 3x +10, then what must be the value of x?

User Luke Redpath
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1 Answer

4 votes

Answer:

ab=de corresponding side of the congruent triangle are equal

5x+6=3x+10

5x-3x=10-6

2x=4

x=4/2=2

2 is your answer

User Prakash Vishwakarma
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7.7k points
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