Question

1) Marty (m = 8 kg) is sitting still in a small fishing boat (40 kg) when he decides to go for a swim. Marty

jumps off of the boat, which causes the boat to have a velocity of 1 m/s. What is the velocity of Marty's
jump?

Answer 1

the velocity of the Marty's Jump is 5 m/s.

Step-by-step explanation:

Given;

mass of Marty, m₁ = 8 kg

mass of the boat, m₂ = 40 kg

velocity of the boat, u₂ = 1 m/s

Let the velocity of the Marty's Jump = u₁

Apply the principle of conservation of momentum;

m₁u₁ = m₂u₂

u₁ = m₂u₂/m₁

u₁ = (40 x 1) / (8)

u₁ = 5 m/s.

Therefore, the velocity of the Marty's Jump is 5 m/s.