Answer:
6.26 g C
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
[Given] 3.14 × 10²³ atoms C
[Solve] grams C
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
Step 3: Convert
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
6.26227 g C ≈ 6.26 g C