Question

If f(x) = 12x² - 5 and g(x) = x + 7 find(fºg)(x).
I need help asap please and thank you

Answer 1

`(f\circ g)(x)=12x^2+168x+583`

Explanation:

We are given the two functions:

`f(x)=12x^2-5\text{ and } g(x)=x+7`

And we want to find:

`(f\circ g)(x)`

This is equivalent to:

`=f(g(x))`

Therefore:

`=f(x+7)`

Then by substitution:

`=12(x+7)^2-5`

Square:

`=12(x^2+14x+49)-5`

Distribute:

`=(12x^2+168x+588)-5`

Simplify:

`=12x^2+168x+583`

Therefore:

`(f\circ g)(x)=12x^2+168x+583`