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What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25?

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Answer:

y= 5\4x - 1

Explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First, rewrite the equation of the given line in the form of y=mx +c.

4X+5y=25

5y= -4X +25

y= -4\5X +5

The gradient of the given line is -4\5

The product of the gradient of perpendicular lines is -1.

(14\5)(gradient of the line) = -1

gradient of the line= -1 divided by (-4\5)

Thus, m=5\4

y=5\4x +C

Substitute a coordinate to find c.

When X= -4, y= -6,

-6 =5\4 (-4) +C

-6= -5 +C

C= 5-6

C= -1

Hence, the equation of the line is

y= 5\4x - 1

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