Answer:
a. The time it will take for the two robots meet
b. The important numbers are;
426 (cm), 5 (cm/second) and 7 (cm/second)
c. Yes, there are variables
d. The equation is 5 cm/s × t + 7 cm/s × t = 426 cm
e. The solution of the equation is, t = 35.5 seconds
f. Yes, the answer is reasonable
Step-by-step explanation:
a. The question being asked is the time duration that will elapse before the two robots meet
b. The important numbers are;
The distance apart from which the two robots start out, d = 426 cm
The speed of the first robot, v₁ = 5 cm/second
The speed of the second robot, v₂ = 7 cm/second
c. The variables are;
The distance apart of the two robots = d
The speed of the first robot = v₁
The speed of the second robot = v₂
The time it takes for the two robots to meet = t
d. The equation is;
v₁ × t + v₂ × t = d
Plugging in the known values of v₁, v₂, we have;
5 cm/s × t + 7 cm/s × t = 426 cm...(1)
e. Solving the equation (1) above gives;
5 cm/s × t + 7 cm/s × t = t × (5 cm/s + 7 cm/s) = t × 12 cm/s = 426 cm
∴ t = 426 cm/(12 cm/s) = 35.5 s
t = 35.5 seconds
f. The time it would take the two robots to meet, t = 35.5 seconds
The answer is reasonable, given that the distance moved by each robot in the given time are;
The distance moved by the first robot, d₁ = 35.5 s × 5 cm/s = 177.5 cm
The distance moved by the second robot, d₂ = 35.5 s × 7 cm/s = 248.5 cm
d₁ + d₂ = 177.5 cm + 248.5 cm = 426 cm.