Question

What is the equation of the line that passes through the point (1, 3) and has a slope of 6?

Answer 1

Answer (assuming it can be point-slope form):

`y-3=6(x-1)`

Explanation:

Use the point-slope formula
`y-y_1 = m (x-x_1)` to write the equation of the line in point-slope form. Substitute
`m`,
`x_1`, and
`y_1` for real values.

`m` represents the slope, so substitute 6 in its place.
`x_1` and
`y_1` represent the x and y values of one point the line intersects, so substitute the x and y values of (1,3) into the equation as well. Substitute 1 for
`x_1` and 3 for
`y_1`. This gives the equation in point-slope form:

`y-(3) = 6(x-(1))\\y-3 = 6(x-1)`