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PLEASE ANSWER ASAP

A farmer is going to divide her 30 acre farm between two crops. Seed for crop A costs $30 per acre. Seed for crop B costs $15 per acre. The farmer can spend at most $600 on seed.
If crop B brings in a profit of $90 per acre and crop A brings in a profit of $160 per acre, how many acres of each crop should the farmer plant to maximize her profit?

2 Answers

5 votes

Answer:

the farmer should plant 40 acres of crop B.

Explanation:

The restriction equations are:

x + y = 40 acres (1) (for areas; x = the area for crop A; y = the area for crop B).

10x + 20y = 700 (2) for the seed cost

or

x + 2y = 70

We have the following system of equations:

x + y = 40

x + 2y = 70

The additional obvious restrictions are x >= 0 and y >= 0.

The objective function is the profit:

F(x, y) = 60x + 70y

According to the conception/ideology of the linear programming method, we need to evaluate the

objective function F(x, y) = 60x + 70y in three points (corner points):

(0, 40), (35, 0) and (10, 30)

We need to find the point where the objective function is maximal:

F(0, 40) = 60*0 + 70*40 = $2,800

F(35, 0) = 60*35 + 70*0 = $2,100

F(10, 30) = 60*10 + 70*30 = $2,700

Follows, the farmer should plant 40 acres of crop B.

User Mohsen Nazari
by
4.9k points
3 votes

Answer:

Rearrange Inequalities

0<= A <=40

0<= B <= 40

A <= -B + 40

A <= -2B + 50

Acres:: A + B <= 40

Seed:: 10A + 20B <= 500

Profit function:: P = 110A + 40B

Explanation:

PLEASE ANSWER ASAP A farmer is going to divide her 30 acre farm between two crops-example-1
User Muhammad Tahir
by
4.9k points