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Find the volumes of the solids whose bases are bounded by the circle with the indicated cross sections taken perpendicular to the axis

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Answer:

Explanation:

The missing information includes finding the volume of the circle x² + y² = 4 from the x-axis of the squares and the equilateral triangles.


x^2 + y^2 = 4

Perpendicular to x-axis


y = √(4 -x^2)

Area of the square =
( √(4-x^2)+ √(4-x^2))^2


= (2 √(4 -x^2))^2 \\ \\ = 4(4-x^2) \\ \\ = 16 - 4x^2

Volume V =
\int ^2_(-2) (16 -4x^2) \ dx


= \Big [ 16x - (4x^3)/(3) \Big]^2_(-2)


= \Big [32 - (32)/(3) \Big] - \Big[-32 +(32)/(3) \Big]


= (128)/(3)

Area of Equilateral triangle


= (1)/(2)* 2 √(4-x^2)* √(3)√(4-x^2)


= √(3)(√(4-x^2))^2


Volume (V )= \int ^2_(-2)√(3) (4 -x^2) \ dx


= 4√(3) \ x - (√(3) \ x^3 )/(3) \Big|^2_(-2) \\ \\ = 16 √(3) - (16√(3))/(3) \\ \\ = (32√(2))/(3)

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