Answer:
(√3·x - 1)(√3·x + 1)(4x - 3)
Explanation:
Note that the last two coefficients are -4 and +3, and the associated factor is (4x - 3).
The first two terms are
12x^3 - 9x^2, which become 3x(4x^2 - 3x) through factoring and then 3x^2(4x - 3).
Therefore, 12x3 – 9x2 – 4x + 3 can be rewritten as:
(4x - 3)(3x^2 - 1).
It's possible to factor 3x^2 - 1, even though 3 is not a perfect square. Write 3x^2 - 1 as (√3·x - 1)(√3·x + 1)
Then 12x3 – 9x2 – 4x + 3 = (√3·x - 1)(√3·x + 1)(4x - 3)