Question

2. What coefficients would balance the following equation?

_C2H6 +_027_C02 +_H20
A. 1C2H6 + 502 – 2002 + 3H20
B. 2C2H6 + 502 + 4002 + 6H20
O C. 2C2H6 + 702 4CO2 + 6H20
O D. 2C2H6 + 1002 > 4CO2 + 6H20

Answer 1

C

Step-by-step explanation:

Assuming you had a few typos in the equations, I would say C

I am going to assume the reaction

_C2H6 + _O2 → _CO2 + _H2O

Right now, there is enough hydrogen to make 3 water molecules, but since oxygen comes in groups of 2, it wouldn't work.

Therefore, we need 2 ethane molecules.

2C2H6 + _O2 → _CO2 + _H2O

Then balance the right side with the carbons and hydrogens

2C2H6 + _O2 → 4CO2 + 6H2O

So we need 4 O2's in carbon dioxide and 3 O2's in water (Since water uses 1 oxygen molecule per 2 hydrogens). Hence we will need 7 oxygens

2C2H6 + 7O2 → 4CO2 + 6H2O

And assuming errors in the typing, C should be the answer (if this matches)