Question

A ball is thrown into the air with an upward velocity of 28ft/s. Its height h in feet after t seconds is given by the function h = -16t^2 + 28t + 8

Answer 1

Answer:

In bold below.

Explanation:

Find derivative which gives the velocity:

V = h' = -32t + 28

At maxm height V = 0 so

-32t + 28 = 0

Time to reach maxm height t = -28/-32 = 0.875 seconds.

So maxm height

= -16(0.875)^2 + 28*0.875 + 8

= 20.25 ft.