Question

If 135 grams of MgCl2 are dissolved in a 1.0 L solutions, what is the molarity of the solution?

Answer 1

Answer: 1.418 M

Step-by-step explanation:

molarity = moles of solute/liters of solution or
`M=(mol)/(L)`

first we have to find our moles of solute (mol), which you can find by dividing the mass of solute by molar mass of solute

mass of solute: 135 g

molar mass of solute: 95.21 g/mol

let's plug it in:

`(135 g)/(95.21 g/mol) = 1.418 mol`

next, we plug it into our original equation:

`(1.418 mol)/(1.0 L) = 1.418 M`