Question

On an average day, a horse might drink 50 L, a sheep might drink 4 L, and a chicken might drink 200 mL. How much water would a farm with 3 horses, 15 sheep, and 12 chickens need for a day?

Answer 1

212.4 L

Explanation:

We have 3 horses, so we can do
`3*50=150\\`. Then we have 15 sheep, so
`15*4=60`. 1000 mL is 1 L, so if we do
`12*200=2400` mL.
`2400/1000=2.4`L, so 150+60+2.4=212.4 L.