Question

A restaurant and dairy are participating in a community digester pilot program within the UMD Industrial Park. The following waste stocks are currently treated in the anaerobic digester: waste cooking oil, glass clippings, and cow manure. There is 200 gallons of waste cooking oil delivered per week, six 50 gallons barrels of glass clippings per week, and 500 Liters of cow manure per day. The feedstocks have the following VS concentrations and methane production potentials:________.

Waste cooking oil: 25,000 mg/L VS; 600 L CH4/g VS Grass Clippings: 15,000 mg/L VS; 300 L CH4/g VS Cow Manure: 5,000 mg/L VS; 150 L CH4/g VS
What is the daily methane production in Liters?

Answer 1

2727000 Liters

Step-by-step explanation:

Determine the daily methane production in liters

For waste cooking oil ;

Delivered amount in liters = 757.082 liters per week

daily = 757.082 / 7 = 108.154 L/day

waste vs concentration = 25,000 mg/L

Its volatile solid = 25000 * 10^-3 (g/l) * 108.154 L/day

= 2703.864 g/day

hence methane production in liters

= 600 L/g * 2703.864 g/day

= 1622318.57 L

For cow manure

Delivered amount in liters = 500 liters / day

Vs concentration = 5000 mg/l

Hence amount of Vs = 5000 * 10^-3 * 500 = 2500 ( g/day)

methane production in liters

= 150 * 2500 = 375000 liters

For glass clippings

Delivered amount in liters per day = 1135.62 / 7 = 162.23 L/day

amount of Vs = 15000 * 10^-3 (g/L) * 162.23 L/day = 2438.45 ( g/day )

hence the methane production in liters

= 300 * 2433.45 = 730035 L

Hence ∑ daily methane production of each waste

= 1622318.57 + 375000 + 730035 = 2727000 Liters