Answer:
Explanation:
The diameter is 0.45 in
The percent error is < 4%
The lower limit of allowance is:
- 0.45 - 4% =
- 0.45*(1 - 0.04) =
- 0.45*0.96 =
- 0.432
Less than 4% error means the diameter should be greater than 0.432 in.
The bolt with the diameter 0.43 in is outside of the allowance and should not go into the package