Question

How many liters of 0. 1107 m kcl(aq) contain 15. 00 g of kcl?.

Answer 1

`\huge \underline\frak \red{Answer}`

number of moles

N = sample mass/molar mass

N= 0.1107/74.6

N= 0.2010 moles of KCL

therefore

molarity = moles/volume

0.1107 = 0.2010/V

V = 0.2010/0.1107

V = 1.815L