Question

Algebra 2
Please help!

Answer 1

3x

Explanation:

`h(x) = \sqrt[3]{x},\: \: k(x) = 27 {x}^(3) \\ \\ (a) \: h(k(x)) = \sqrt[3]{27 {x}^(3) } \\ \\ = \sqrt[3]{ {(3x)}^(3) } \\ \\ = {(3x)}^{3 * (1)/(3) } \\ \\ = 3x`

Answer 2

3x

Explanation:

Since k(x)=27x^3, we replace it in h( k(x) ), we will get:

h(27x^3)

Given that h(x)={3}√x [my keyboard doesn't support cubic root]

= {3}√(27x^3)

27 is 3^3,

Simplifying, the final answer is:

3x.