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How many iron atoms are in 7.890 g of iron?
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How many iron atoms are in 7.890 g of iron?

User Calvin Godfrey
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1 Answer

4 votes

Answer:

mole = reactingmass = 7.890= 0.142 mol

molarmass 55.8

atoms = mol × alvagadro constant

0.142 × 6.02 × 10^23

=8.5484 × 10^22 Atoms

User Louis Sayers
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