Answer:
a)
![(Ws)/(Es) = (200)/(1+1.2s)](https://img.qammunity.org/2022/formulas/engineering/college/3ku0b7amnrsew763fko28ialliz90s6l7r.png)
b) attached below
c) type zero system
d) k >
![(g)/(200)](https://img.qammunity.org/2022/formulas/engineering/college/chosuh6xiclko2gmw5ah6s3tj60ulw0xv2.png)
e) The gain K increases above % error as the steady state speed increases
Step-by-step explanation:
Given data:
Motor voltage = 12 v
steady state speed = 200 rad/s
time taken to reach 63.2% = 1.2 seconds
a) The transfer function of the motor from voltage to speed
let ;
be the transfer function of a motor
when i/p = 12v then steady state speed ( k1 ) = 200 rad/s , St ( time constant ) = 1.2 sec
hence the transfer function of the motor from voltage to speed
=
![(Ws)/(Es) = (200)/(1+1.2s)](https://img.qammunity.org/2022/formulas/engineering/college/3ku0b7amnrsew763fko28ialliz90s6l7r.png)
b) draw the block diagram of the system with plant controller and the feedback path
attached below is the remaining part of the detailed solution
c) The system is a type-zero system because the pole at the origin is zero
d) ) k >
![(g)/(200)](https://img.qammunity.org/2022/formulas/engineering/college/chosuh6xiclko2gmw5ah6s3tj60ulw0xv2.png)