445,150 views
8 votes
8 votes
Number 29 plz help physics

Number 29 plz help physics-example-1
User PlushEngineCell
by
2.9k points

1 Answer

16 votes
16 votes

Answer:

a. E = 900000 J = 900 KJ

b. ΔT = 8.18 °C

c. Cost = $ 7.2

Step-by-step explanation:

a.

The energy can be given by:


image

where,

E = Energy = ?

P = Power = 500 W

t = time = (0.5 h)(3600 s/1 h) = 1800 s

Therefore,


image

E = 900000 J = 900 KJ

b.

The change in temperature of room air is given by the following formula:


image (since 50% of energy is used to heat air)

where,

m = mass of air = 50 kg

C = specific heat of air = 1.1 KJ/kg.°C

ΔT = Change in temperature of air = ?

Therefore,


image

ΔT = 8.18 °C

c.

First, we will calculate the total energy consumed:


image

Now, for the cost:


image

Cost = $ 7.2

User Jozala
by
3.1k points