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In ΔMNO, the measure of ∠O=90°, the measure of ∠N=62°, and NO = 66 feet. Find the length of MN to the nearest tenth of a foot.

User Ilian
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1 Answer

5 votes

Answer:

140.6 feet

Explanation:

In ΔMNO, the measure of ∠O=90°, the measure of ∠N=62°, and NO = 66 feet. Find the length of MN to the nearest tenth of a foot.

Step 1

We have to find Angle M

Sum of angles in a triangle = 180°

M + N + O = 180°

M = 180° - ( N + O)

M = 180° - ( 90° + 62°)

M = 28°

Step 2

We find the length of MN

We solve using Sine rule

MN/sin O = NO/sin M

MN/sin 90 = 66/sin 28

Cross Multiply

MN = sin 90 × 66/sin 28

MN = 140.58 feet

Approximately = 140.6 feet

User Fernando Basso
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