Question

Bilal and Charlie have some sweets. Bilal has 4 times as many sweets as Charlie. Bilal gives Charlie 15 of his sweets and now they have the same amount. How many sweets do they have altogether?

Answer 1

To find the total number of sweets they have altogether, we can set up an equation based on the given information and solve for the number of sweets each person has. Charlie initially has 10 sweets and Bilal initially has 40 sweets. Together, they have 50 sweets in total.

Step-by-step explanation:

To solve this problem, let's assign a variable to represent the number of sweets Charlie has. Let's call it C.

According to the given information, Bilal has 4 times as many sweets as Charlie, so Bilal has 4C sweets.

Bilal gives 15 sweets to Charlie, which means Charlie now has C + 15 sweets. Bilal now has 4C - 15 sweets.

Since they now have the same amount of sweets, we can set up the equation: C + 15 = 4C - 15.

Simplifying the equation, we get 30 = 3C.

Dividing both sides by 3, we find that C = 10.

So Charlie initially had 10 sweets, and Bilal initially had 4 times as many, which is 40 sweets.

Altogether, they now have 10 + 40 = 50 sweets.

Answer 2

50

Step-by-step explanation:

The computation of the number of sweets they do have altogether is as follows:

Let us assume Charlie sweets be x

So bilal sweets is 4x

Now Bilal gives Charlie 15 of his sweets due to which they must have the same amount

4x - 15 = x + 15

4x -x = 15 + 15

3x = 30

x = 10 = Charlie sweets

Bilal sweets = 4x = 4(10) = 40

So the total no of sweets held by them is 50