Question

HELP MEEEEEEEEEEEEEEEE ASAP.....NO LINKS & NO TROLLING

which statement about of y=5x^2+17x+6 is true


A. the zeros of y=5x^(2)+17x+6 are 3 and( 2)/(5), because y=(x+3)(5x+2)


B. the zeros of y=5x^2+17x+6 are 3 and 2/5, because y=(x-3)(5x-2)


C. the zeros of y=5x^2+17x+6 are -3 and -2/5, because y=(x+3)(5x+2)


D. the zeros of y=5x^2+17x+6 are -3 and -2/5, because y=(x-3)(5x-2)

C IS THE ANSWER

Answer 1

• y=5x²+17x+6

ac is 5(6)=30

• y=5x²+5x+2x+6
• y=5x(x+3)+2(x+3)
• y=(x+3)(5x+2)

So the zeros are

• -3 and -2/5

Option C is correct

Answer 2

C

`y=(5x+2)(x+3)`

`\implies x=-\frac25,\ \ x=-3`

Explanation:

Factor
`y=5x^2+17x+6`

Multiply the coefficient of
`x^2` and the constant:

⇒ 5 x 6 = 30

Find factors of 30 that add together to make the coefficient of
`x`:

⇒ 2 and 15

Rewrite 17x as 15x + 2x:

`\implies y=5x^2+15x+2x+6`

Group:

`\implies y=(5x^2+15x)+(2x+6)`

Factor brackets:

`\implies y=5x(x+3)+2(x+3)`

Factor out common term
`(x + 3)`:

`\implies y=(5x+2)(x+3)`

To find the zeroes, set y to zero and solve for x:

`\implies (5x+2)(x+3)=0`

`\implies 5x+2=0 \ \ \textsf{and} \ \ x+3=0`

`\implies x=-\frac25,\ \ x=-3`