Question

In ΔQRS, the measure of ∠S=90°, RS = 2.2 feet, and QR = 4.5 feet. Find the measure of ∠Q to the nearest tenth of a degree.

Answer 1

`Q = 29.3^\circ`

Explanation:

Given

`\angle S = 90`

`RS = 2.2ft`

`QR = 4.5ft`

See attachment for ΔQRS

To calculate <Q, we make use of:

`sin\ Q = (Opposite)/(Hypotenuse)`

Where

`Opposite = RS`

`Hypotenuse = QR`

`sin\ Q = (RS)/(QR)`

`sin\ Q = (2.2)/(4.5)`

`sin\ Q = 0.4889`

Take arc sin of both side

`Q = sin^(-1)(0.4889)`

`Q = 29.3^\circ`