Answer:
yz)
log(
z
y
)
.(zx)
x
.(xy)
=
⎣
⎢
⎡
.x
⎦
⎥
⎤
×
.y
.z
=x
=(x
logz−logy
).(y
logx−logz
).(z
logy−logx
logy
logz
.
logx
=1
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