Question

PLEASE HELP ME SOLVE ASAP​

Answer 1

a) The distance after 1 minute will be x = 600 m.

b) The distance of vertical drop from A to B is
`\Delta y=17658\: m`.

Step-by-step explanation:

Let's use the parabolic motion equations. Here we have a horizontal initial velocity, and knowing that the horizontal velocity is a constant we have:

a)

`v_(x)=(\Delta x)/(\Delta t)` (1)

Where:

• v(x) is the horizontal velocity (v(x) = 36 km/h = 10 m/s)
• Δx is the displacement
• Δt is the time (Δt = 1 min = 60 s)

Usinf (1) we find Δx:

`\Delta x=v_(x)\Delta t`

`\Delta x=10*60=600 m`

Therefore, the distance after 1 minute will be x = 600 m

b)

Here we need to find Δy = y(A)-y(B), this is the distance of vertical drop from A to B.

Using the following equation we will get it:

`y_(B)=y_(A)+v_(iy)t-(1)/(2)gt^(2)`

Let's recall that the initial velocity in the y-direction is 0.

`y_(A)-y_(B)=0t+(1)/(2)gt^(2)`

`\Delta y=(1)/(2)gt^(2)`

`\Delta y=(1)/(2)(9.81)(60)^(2)`

`\Delta y=17658\: m`

Therefore, the distance of vertical drop from A to B is
`\Delta y=17658\: m`.

I hope it helps you!