{y}^(2) + (3y)/(2) = (27)/(2)​

Question

`{y}^(2) + (3y)/(2) = (27)/(2)`​

Answer 1

-9/2, 3

Explanation:

Multiply by 2 on both sides and move right side to left, get

`2y^2+3y-27=0`

Use the quadratic formula

`y=(-3\pm√(3^2+2*4*27))/(4)=(-3\pm√(225))/(4)=(-3\pm15)/(4)`

so y=-9/2, 3

Answer 2

Answer: y= 3, - 9/2

Explain