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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8
6d5 – 4c3d2 + 3c2d3 – 4cd4 + 8
6d5 – 4c3d2 + 5c2d3 – 12cd4 + 8
6d5 – 2c3d2 – 3c2d3 – 4cd4 + 8

User Grateful
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2 Answers

4 votes

Answer:

a

Explanation:

just use it mannnn

User Camille Khalaghi
by
4.5k points
3 votes

Answer:

a.
x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8

Explanation:

Given that


8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9

Now

if one is added i.e.


2d^5 - c^3d^2 + 8cd^4 + 1

Now let us assume the other polynomial be x

So,


8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 = x + (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\x = 8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\


x = (8d^5 - 2d^5) + (-3c^3d^2 + c^3d^2) + 5c^2d^3+ (-4cd^4-8cd^4) + (9-1)\\\\x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8

User Baske
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4.0k points