Answer:
I = 1.09 A
Step-by-step explanation:
Here, 5 ohm and 12 ohm resistor are connected in parallel. Using the parallel combination of resistors as follows :
![(1)/(R)=(1)/(R_1)+(1)/(R_2)\\\\(1)/(R)=(1)/(5)+(1)/(12)\\\\ R=3.52\ \Omega](https://img.qammunity.org/2022/formulas/physics/high-school/8m7qlmy8jq86s0mbdaz7772e7pqfpdxybp.png)
Now R and 2 ohm resistors are in series. Let the equivalent be
. So,
![R_(eq)=3.52+2\\\\=5.52\ \Omega](https://img.qammunity.org/2022/formulas/physics/high-school/hw7rj7g00pstpvb6f1kwguo8yhp37oauv7.png)
Let I be the current. Using Ohm's law,
V = IR
![I=(V)/(R_(eq))\\\\I=(6)/(5.52)\\\\I=1.086\ A](https://img.qammunity.org/2022/formulas/physics/high-school/4vw1pdf4221ug53h7qdzjmp38w4xmcy416.png)
or
I = 1.09 A
So, the correct option is (c).