Answer:
Step-by-step explanation:
Br₂(g) + Cl₂(g) => 2BrCl(g)
excess 2.74mole ?moles
Rxn ratio is 1mole Cl₂(g) : 2mole BrCl which means the yield of BrCl must be larger mole value than the Cl₂(g) mole value. This is accomplished by multiplying the given moles Cl₂(g) by a ratio of coefficients that will make the results larger.
moles BrCl(g) produced = 2/1(2.47mole BrCl(g) = 5.48 mole BrCl(g)