Question

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The specific heat capacity of water is 4.184 J/g°C. How much heat is required to heat 500.0 g of water from 50.0°C to 100.°C?

Answer 1

Answer: 104,600

Explanation: subtract final temp from initial temp = 50 then multiply by grams = 25,000 then multiply by J = 104,600

Answer 2

104600 Joules

Step-by-step explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since, M = 500.0 g

C = 4.184 J/g°C

Φ = 100°C - 50°C = 50°C

Q = 500g x 4.184J/g°C x 50°C

Q= 104600 Joules

Thus, it takes 104600 Joules of heat energy to heat the water