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Please help im doing my girl friend work and i dont know not a thing

The admission fee at a John Hay basketball game is $1.50 for students and $4.00 for adults. On a certain day, 2200 people enter the fair and $5050 is collected.

How many of each type of ticket did they sell?

Student:
and

Adult

User Naktibalda
by
6.2k points

1 Answer

4 votes

Answer:

See below, please!

Explanation:

We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.

So since the student ticket is $1.50, and adult is $4, we can set up the following equation:
1.5x+4y=5050, since they collected $5050 total.

We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.

Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.

Hope this helped!

User Naveen Ramawat
by
6.1k points
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