9514 1404 393
Answer:
Explanation:
The tangent of the angle can be found using the identity for the tangent of the difference of angles.
tan(α-β) = (tan(α) -tan(β))/(1 +tan(α)tan(β))
The tangent of the angle of each vector is the ratio of the j coefficient to the i coefficient.
tan(α) = -2/3
tan(β) = 4/7
tan(α-β) = (-2/3 -4/7)/(1 +(-2/3)(4/7))
= (-14-12)/(21 -8) = -26/13 = -2
Then the magnitude of the angle between the vectors is ...
arctan(2) ≈ 63.43°