Question

Find the equation of the straight line passing through the point (0, 1)

which is perpendicular to the line
y=-2x + 2

Answer 1

Explanation:

y=-2x+2

point(0,1)

m1=2=m1×m2=-1

-2×m2=-1=-2m=-1(÷ both sides by -2)

M2=1/2

equation

1/2=y-1/x-0

2(y-1)/(x-0)1=2y-2=x-0

y=mx+c=2y=x-0+2

2y=x+2 (÷all sides by 2)

Ans=y=1/2x+1