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Solve simultaneously


{2}^(x) + {3}^(y) = 9 \\ {2}^(x + 2) - {3}^(y + 1) = 8


User Fgalan
by
3.6k points

2 Answers

1 vote

Answer:

2x+3y=9

2x+2-3y+1=8

2x-3y=8

2x-3y+3y=8+3y

2x=8+3y

2x=8+3y

2 2

x=8+3y

2

2(x) +3y=9

2* (8+3y)/2 +3y=9

(16+6y)/2)+3y=9

2*(16+6y)/2)+3y=9

16+6y+6y=18

6y+6y=18-16

12y=2

12y = 2

12 12

y=2

12

y=0.16666666666667

2x+3 (0.16666666666667)=9

2x+0.5=9

2x=9-0.5

2x=8.5

2x = 8.5

2 2

x=8.5

2

x=4.25

User Franza
by
4.7k points
4 votes

Answer:

I hope this helps you :)

Solve simultaneously {2}^(x) + {3}^(y) = 9 \\ {2}^(x + 2) - {3}^(y + 1) = 8 ​-example-1
Solve simultaneously {2}^(x) + {3}^(y) = 9 \\ {2}^(x + 2) - {3}^(y + 1) = 8 ​-example-2
User Wilcroft
by
4.2k points