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42 votes
42 votes
An engine raises 120kg of water through a height of 40m in 30s what is the power of the engine?(g=10m/s2​

User SpacePotatoes
by
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1 Answer

20 votes
20 votes

Answer:

4800J/s

Explanation:

m = 120kg

H = 40m

t = 30sec

Input energy = 120 × g × H = mgn

Ei = 120 × 40 × 30 = 144000J

Energy per sec, E1 = 144000 ÷ 30 = 4800J/s

Power input = 4800J/s

User Jeff Burdges
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3.2k points