Answer: 169.3 g of
will be produced
Step-by-step explanation:
To calculate the moles, we use the equation:
moles of
moles of
According to ideal gas equation:
P = pressure of gas = 1 atm (STP)
V = Volume of gas = 42.7 L
n = number of moles = ?
R = gas constant =
T =temperature =
(at STP)
According to stoichiometry:
3 moles of
reacts with = 2 moles of aluminium
Thus 1.90 moles of
reacts with=
moles of aluminium
Thus
is the limiting reagent as it limits the formation of product.
As 3 moles of
give = 2 moles of
Thus 1.90 moles of
give =
of
Mass of
Thus 169.3 g of
will be produced from the given masses of both reactants.