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What is the total pressure in a 10.0L flask which contains 0.200mol of H2 and 0.215mol of N2​

User Pyt
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1 Answer

2 votes

Answer:

0.998 atm.

Step-by-step explanation:

NOTE: The temperature is missing in the above question and the value is 20 °C

From the question given above, the following data were obtained:

Volume (V) = 10.0 L

Number of mole of H₂ = 0.2 mole

Number of mole N₂ = 0.215 mole

Temperature (T) = 20 °C

Total pressure (P) =?

Next, we shall determine the total number of mole in flask. This can be obtained as follow:

Number of mole of H₂ = 0.2 mole

Number of mole of N₂ = 0.215 mole

Total number of mole (n) =?

n = mole of H₂ + mole of N₂

n = 0.2 + 0.215

n = 0.415 mole

Thus, the total number of mole in the flask is 0.415 mole

Next, we shall convert 20 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 20 °C + 273

Temperature (T) = 293 K

Finally, we shall determine the total pressure in the flask. This can be obtained as follow:

Volume (V) = 10.0 L

Total number of mole (n) = 0.415 mole

Temperature (T) = 293 K

Gas constant (R) = 0.0821 atm.L/Kmol

Total pressure (P) =?

PV = nRT

P × 10 = 0.415 × 0.0821 × 293

Divide both side by 10

P = (0.415 × 0.0821 × 293) / 10

P = 0.998 atm.

Therefore, the total pressure in the flask is 0.998 atm.

User NJ Bhanushali
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