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Help me out please an thank you

Help me out please an thank you-example-1

1 Answer

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Given:

The graph of a parabola.

To find:

The equation of the parabola.

Solution:

From the given graph, it is clear that the vertex of the parabola is at point (0,0) and it is a horizontal parabola.

The general equation of a horizontal parabola is:


x=ay^2

Where, a is a constant.

If a<0, then the parabola opens left and if a>0, then the parabola opens right.

Equations in options B and D are of the form
x=ay^2 but a<0 in option B and a>0 in option D.

In the given graph the parabola opens right, so the value of a mus be a positive number. So, the required equation is:


x=(1)/(6)y^2

Therefore, the correct option is D.

User Adrianopolis
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